# Math tricks, brain twisters, and puzzles

## Joseph Degrazia

Language: English

Pages: 158

ISBN: 0517336499

Format: PDF / Kindle (mobi) / ePub

Math tricks, brain twisters, and puzzles

200 puzzles and problems -- hours of fun.

of the two others and its burning time is four hours. The two outer candles are of different thicknesses from the center candle and from each other. One can burn 41 hours and the other one 9. At the beginning of a Thankgiving dinner the candlestick was placed on the table and the three candles were lighted. When the dinner was over the candles were snuffed out by the host. Then one of the guests did a little measuring and found that the heads of the three candles formed a slanting straight line.

star. Still more difficult than the previous problem is that of the seven-pointed star shown in Fig. 14. (Disregard dotted lines for the moment.) The seven lines of the figure intersect at 14 points altogether, and the problem is to place the numbers 1 to 14 in the 14 circles so that in every case the sum of the numbers along a line adds up to 30. So far, no strictly mathematical solution of this problem has been found, though certain rules have been discovered that facilitate the empirical

on the average, he or she has won or lost dollars per game. Moreover, they figure out that Eric has lost $504 more than John, and that Beatrice has won $2,376 more than Margie. These facts are sufficient for you to find out who is married to whom, in case you are interested. 108 SOLUTIONS SOLUTIONS 1 - The empty bottle costs $2.50, the wine $42.50, that is, $40 more than the bottle. If you prefer an equation: b + (b + 40) = 45; b = 2.50. 2- The dealer was right. The car that brought him a

figure out the distance. It is 61 miles. 97-If we call the distance between Ashton and Beale x, and that between Beale and Carter y, we have the following equations: 25 = y -5 + E = + 10. The three sides of the triangle measure 20, 15 and 30 miles. The speeds of the two boats are in the ratio of 40 to 25, or 8 to 5. 98-If x is the distance the head of the army advanced while the dispatch rider rode from the rear to the head of the army, we have the equation (50 + x): x = x: (50 - x), which gives

circles of the inner pentagon of the figure and then try to discover a method for finding out the numbers pertaining to the five points of the pentagram. Let us start by calling x the unknown number at the point G. Then the sum of the numbers along the two lines intersecting at G is 2s - x. Now all numbers with the exception of F, H and D are accounted for. Moreover, we can state that F + H = s-(A + B) and, consequently, 2s-x +s - (A + B) +D=S= .Hencex=s+D-(A+B). This implies that the number at